1 2 3 4 5 6 7 8 9 10

Run this program and discuss the remaining output with
your TA

The address of argument a is effff7ac The address of argument b is effff7b0 The address of argument c is effff75f The address of argument d is effff75e The address of argument f is effff750 The address of argument g is effff748

3 bytes

81 bytes 1 byte
15 bytes 8 bytes

Note the size of the (stack) addresses!! Why are they not at 4-byte intervals?

January 22, 1999

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