Assuming linear probing, consider:

To retrieve a value with key 80:

P = H(80) = 0. OCCUPIED, but key=75.

P = (1 + 0) mod 10 = 1. EMPTY.

Suppose we delete 35:

To retrieve a value with key 25:

P = H(25) = 5. OCCUPIED, but key=15.

P = (1+5) mod 10 = 6. DELETED.

P = (1+6) mod 10 = 7. OCCUPIED, but key=17.

P = (1+7) mod 10 = 8. OCCUPIED, but key=8.

P = (1+8) mod 10 = 9. OCCUPIED by 25!